What direction does the sun rise on the longest day of the year ?
Q. Also, what direction does it set ? and the shortest day of the year its direction of its rise and its direction when it sets ? please dont give me a detailed answer only the directions.Im in Europe UK. Thank you...
Asked by Mainline - Sun Jan 3 15:23:42 2010 - - 6 Answers - 0 Comments
A. And south-east and south-west in mid-winter. But UK is far enough north for there to be quite a difference depending on whether you're on the south coast of England or the north coast of Scotland and even more if you're in the Shetlands.
Answered by RobRoy - Sun Jan 3 15:35:05 2010
Q. Also, what direction does it set ? and the shortest day of the year its direction of its rise and its direction when it sets ? please dont give me a detailed answer only the directions.Im in Europe UK. Thank you...
Asked by Mainline - Sun Jan 3 15:23:42 2010 - - 6 Answers - 0 Comments
A. And south-east and south-west in mid-winter. But UK is far enough north for there to be quite a difference depending on whether you're on the south coast of England or the north coast of Scotland and even more if you're in the Shetlands.
Answered by RobRoy - Sun Jan 3 15:35:05 2010
What direction is the pilot flying and what is the speed relative to the ground?
Q. A pilot is flying at an air speed of 241 mph in a wind blowing 20.4 mph from the east. In what direction must the pilot head in order to fly due north?(Round to the nearest tenth degree with a direction E or W from north) What is the pilot's speed relative to the ground? I guess it has to do with reslutants?? Thanks for any guidance and answers.
Asked by mdetaos - Fri Nov 17 15:16:19 2006 - - 4 Answers - 0 Comments
A. Lots of unnecessary complications here. Airspeed is the hypotenuse. 20.4 is the side opposite the angle we are looking for. The heading, east of north, must be at angle sin^-1(20.4/241). Speed relative to the ground is the third side of the triangle, and is sqrt(241^2 - 20.4^2) Zidane has got the angles all wrong. The wind is from the east. We want to fly due north. That's where the right angle is. 241 is the hypotenuse of the triangle. The wind serves to make the ground speed less than 241, not greater.
Answered by garyp - Fri Nov 17 15:50:04 2006
Q. A pilot is flying at an air speed of 241 mph in a wind blowing 20.4 mph from the east. In what direction must the pilot head in order to fly due north?(Round to the nearest tenth degree with a direction E or W from north) What is the pilot's speed relative to the ground? I guess it has to do with reslutants?? Thanks for any guidance and answers.
Asked by mdetaos - Fri Nov 17 15:16:19 2006 - - 4 Answers - 0 Comments
A. Lots of unnecessary complications here. Airspeed is the hypotenuse. 20.4 is the side opposite the angle we are looking for. The heading, east of north, must be at angle sin^-1(20.4/241). Speed relative to the ground is the third side of the triangle, and is sqrt(241^2 - 20.4^2) Zidane has got the angles all wrong. The wind is from the east. We want to fly due north. That's where the right angle is. 241 is the hypotenuse of the triangle. The wind serves to make the ground speed less than 241, not greater.
Answered by garyp - Fri Nov 17 15:50:04 2006
What causes the direction of currents in the mantle in the Earth?
Q. Does the direction of the Earth's rotation affect the direction of currents in the mantle? I know that the currents are caused by the mantle heating and cooling, and thus rising and falling, and I know that the currents in the mantle cause the tectonic plates to move. But I really want to know what affects the direction of those currents.
Asked by Adam Wall - Wed Sep 16 16:20:58 2009 - - 1 Answers - 0 Comments
A. There's an awful lot we just don't know about tectonics. You've hit on one of them. I've spent time staring at maps of the Earth's plates trying to visualize any pattern of motion underneath and to me it seems completely random. It's certainly possible the Earth's rotation influences the mantle's convection. There's probably a complex group of causes each affecting every other, like local rock composition, local variations in heat rising from below, lateral currents from some other sources, interference from subducted crust and who knows what else. There's a LOT of research going on to understand this. If this interests you enough, might you have found your life's calling? Good minds are certainly needed.
Answered by NoPlate - Wed Sep 16 20:42:02 2009
Q. Does the direction of the Earth's rotation affect the direction of currents in the mantle? I know that the currents are caused by the mantle heating and cooling, and thus rising and falling, and I know that the currents in the mantle cause the tectonic plates to move. But I really want to know what affects the direction of those currents.
Asked by Adam Wall - Wed Sep 16 16:20:58 2009 - - 1 Answers - 0 Comments
A. There's an awful lot we just don't know about tectonics. You've hit on one of them. I've spent time staring at maps of the Earth's plates trying to visualize any pattern of motion underneath and to me it seems completely random. It's certainly possible the Earth's rotation influences the mantle's convection. There's probably a complex group of causes each affecting every other, like local rock composition, local variations in heat rising from below, lateral currents from some other sources, interference from subducted crust and who knows what else. There's a LOT of research going on to understand this. If this interests you enough, might you have found your life's calling? Good minds are certainly needed.
Answered by NoPlate - Wed Sep 16 20:42:02 2009
What direction does the sunset appear to move on the horizon over the year?
Q. I'm doing some observations of sunsets and was just wondering, along the span of the year, what direction does the sun appear to move along the western horizon for sunsets? I know it does not actually move, but what is its apparent movement direction? Thank you!
Asked by Megan P - Wed Apr 29 14:35:13 2009 - - 2 Answers - 0 Comments
A. Yes, for the Northern Hemisphere, it appears to head northward in the summer, and southward in the winter. In the Southern Hemisphere, you will get the opposite effect
Answered by Geology Rock Star - Wed Apr 29 14:39:10 2009
Q. I'm doing some observations of sunsets and was just wondering, along the span of the year, what direction does the sun appear to move along the western horizon for sunsets? I know it does not actually move, but what is its apparent movement direction? Thank you!
Asked by Megan P - Wed Apr 29 14:35:13 2009 - - 2 Answers - 0 Comments
A. Yes, for the Northern Hemisphere, it appears to head northward in the summer, and southward in the winter. In the Southern Hemisphere, you will get the opposite effect
Answered by Geology Rock Star - Wed Apr 29 14:39:10 2009
What is the direction of frictional force when a car is going around a circular race track?
Q. From what I understand, the direction of centripetal force is always directed towards the center of the circular track. But what is the direction of frictional force? And why is it that if the tangential force is greater than frictional force, the car will skid?
Asked by Freezing Temperature - Mon Jul 19 22:21:21 2010 - - 2 Answers - 0 Comments
A. I know that the frictional force is inwards toward the center of the circle. I'm not too sure about the second part, are you sure that statement is true?
Answered by Mark Est - Mon Jul 19 22:39:10 2010
Q. From what I understand, the direction of centripetal force is always directed towards the center of the circular track. But what is the direction of frictional force? And why is it that if the tangential force is greater than frictional force, the car will skid?
Asked by Freezing Temperature - Mon Jul 19 22:21:21 2010 - - 2 Answers - 0 Comments
A. I know that the frictional force is inwards toward the center of the circle. I'm not too sure about the second part, are you sure that statement is true?
Answered by Mark Est - Mon Jul 19 22:39:10 2010
What are the magnitude and direction of the hawk's velocity relative to the ground?
Q. You are in a hot-air balloon that, relative to the ground, has a velocity of 6.2 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 1.8 m/s. What are the magnitude and direction of the hawk's velocity relative to the ground?
Asked by polly - Sun Sep 16 20:00:35 2007 - - 1 Answers - 0 Comments
A. Assuming that the hawk's direction is relative to the balloon. Then we have a vector sum of (6.2,0) + (0,1.8) = (6.2,1.8). Magnitude = 6.456 m/s, angle = 16.189 deg = 16.189 deg N of E.
Answered by kirchwey - Tue Sep 18 10:51:52 2007
Q. You are in a hot-air balloon that, relative to the ground, has a velocity of 6.2 m/s in a direction due east. You see a hawk moving directly away from the balloon in a direction due north. The speed of the hawk relative to you is 1.8 m/s. What are the magnitude and direction of the hawk's velocity relative to the ground?
Asked by polly - Sun Sep 16 20:00:35 2007 - - 1 Answers - 0 Comments
A. Assuming that the hawk's direction is relative to the balloon. Then we have a vector sum of (6.2,0) + (0,1.8) = (6.2,1.8). Magnitude = 6.456 m/s, angle = 16.189 deg = 16.189 deg N of E.
Answered by kirchwey - Tue Sep 18 10:51:52 2007
What direction and what happens to the strength help please?
Q. An electron travels straight up in a region where the magnetic field vector points due north. What is the direction of the resulting force on the electron? If you move twice the distance from a long, straight current-carrying wire, what happens to the strength of the magnetic field? How would I figure this out? Any help is highly appreciated thanks!
Asked by Life Goes On - Sat May 2 19:47:41 2009 - - 1 Answers - 0 Comments
A. I'm sure this stuff is in your physics book Good Luck
Answered by Dave Cannan - Tue May 5 00:56:04 2009
Q. An electron travels straight up in a region where the magnetic field vector points due north. What is the direction of the resulting force on the electron? If you move twice the distance from a long, straight current-carrying wire, what happens to the strength of the magnetic field? How would I figure this out? Any help is highly appreciated thanks!
Asked by Life Goes On - Sat May 2 19:47:41 2009 - - 1 Answers - 0 Comments
A. I'm sure this stuff is in your physics book Good Luck
Answered by Dave Cannan - Tue May 5 00:56:04 2009
What direction is the correct one for a cieling fan to run in the winter time?
Q. When looking at a cieling fan the blades will move either left to right or right to left. There is a correct direction for summer or winter.
Asked by babygrldog - Tue Nov 20 20:02:23 2007 - - 13 Answers - 0 Comments
A. The blades on your ceiling fan should be going clock-wise to "suck" up the heat and recirculate it. In the summertime, the blades go counter clock-wise to bring the cool air down.
Answered by Resident Insomniac - Tue Nov 20 20:08:54 2007
Q. When looking at a cieling fan the blades will move either left to right or right to left. There is a correct direction for summer or winter.
Asked by babygrldog - Tue Nov 20 20:02:23 2007 - - 13 Answers - 0 Comments
A. The blades on your ceiling fan should be going clock-wise to "suck" up the heat and recirculate it. In the summertime, the blades go counter clock-wise to bring the cool air down.
Answered by Resident Insomniac - Tue Nov 20 20:08:54 2007
What direction would you point a telescope to see the big bang?
Q. If you could build a telescope that can see light from 13-14 billion light years away, then you could see light from the early universe, no? Is it correct that you could point that telescope in any direction and pick up radiation from the early expansion of the universe?
Asked by Christopher L - Mon May 14 10:01:15 2007 - - 10 Answers - 0 Comments
A. It doesn't matter what direction you point the telescope in: the fossil radiation from the Big Bang comes from every direction. So the answer to the second part of your question is "yes". We can build such telescopes and have done so, e.g. the COBE and WMAP satellites. The important thing to realize is that because of the expansion of the Universe the radiation has been redshifted into the microwave region of the spectrum; it is no longer detectable as visible light.
Answered by Astronomer1980 - Mon May 14 10:06:26 2007
Q. If you could build a telescope that can see light from 13-14 billion light years away, then you could see light from the early universe, no? Is it correct that you could point that telescope in any direction and pick up radiation from the early expansion of the universe?
Asked by Christopher L - Mon May 14 10:01:15 2007 - - 10 Answers - 0 Comments
A. It doesn't matter what direction you point the telescope in: the fossil radiation from the Big Bang comes from every direction. So the answer to the second part of your question is "yes". We can build such telescopes and have done so, e.g. the COBE and WMAP satellites. The important thing to realize is that because of the expansion of the Universe the radiation has been redshifted into the microwave region of the spectrum; it is no longer detectable as visible light.
Answered by Astronomer1980 - Mon May 14 10:06:26 2007
What direction do you glue the tracks in on a quick weave?
Q. I've tried making one before but the front wasn't quite right. I'd like to leave some hair out at the front and I'm wondering what direction I should be gluing the tracks in for the best effect. Should it follow the horsehoe pattern like the tracks at the back or should it be something else?
Asked by beauty4 - Fri Dec 18 09:30:03 2009 - - 1 Answers - 0 Comments
A. horse hair... hahahahahahah
Answered by Loretta S - Fri Dec 18 09:41:41 2009
Q. I've tried making one before but the front wasn't quite right. I'd like to leave some hair out at the front and I'm wondering what direction I should be gluing the tracks in for the best effect. Should it follow the horsehoe pattern like the tracks at the back or should it be something else?
Asked by beauty4 - Fri Dec 18 09:30:03 2009 - - 1 Answers - 0 Comments
A. horse hair... hahahahahahah
Answered by Loretta S - Fri Dec 18 09:41:41 2009
What is the acceleration in the y direction of the astronaut formula; how is it derived?
Q. Suppose we have a rocket that has an acceleration of 9.26 m/s2 in the x direction. What would the acceleration in the y direction of an astronaunt be inside the rocket. Assume that the astronaunt is on Earth and that there is only an x (horizontal) and y (vertical) direction.
Asked by Damien - Thu Jul 1 12:01:10 2010 - - 2 Answers - 0 Comments
Q. Suppose we have a rocket that has an acceleration of 9.26 m/s2 in the x direction. What would the acceleration in the y direction of an astronaunt be inside the rocket. Assume that the astronaunt is on Earth and that there is only an x (horizontal) and y (vertical) direction.
Asked by Damien - Thu Jul 1 12:01:10 2010 - - 2 Answers - 0 Comments
What is the magnitude and direction of the magnetic field to keep the two charges traveling?
Q. An electron and a proton enter a magnetic field traveling south at 10 m/s, separated by a distance of 0.01m. What is the magnitude and direction of the magnetic field that would be required to keep the two charges traveling in their original direction, undeflected?
Asked by mike phelps - Mon Jul 19 14:50:25 2010 - - 1 Answers - 0 Comments
A. We want qvB = kq^2/r^2 or B = kq/(vr^2) = 8.98755E9*1.6021774E-19/( 10*0.01^2) = 1.439965E-6 T. The direction of B must be perpendicular to the plane containing the two particle paths. The direction relative to the plane is best described by assuming an observer traveling in the particle velocity direction and oriented such that the electron is to the observer's left and the proton is to the right. B will then be in the observer-frame "up" direction. This will result in F(p) being directed "right" and F(e) "left"; i.e., opposing the attractive electric forces.
Answered by kirchwey - Wed Jul 21 11:01:19 2010
Q. An electron and a proton enter a magnetic field traveling south at 10 m/s, separated by a distance of 0.01m. What is the magnitude and direction of the magnetic field that would be required to keep the two charges traveling in their original direction, undeflected?
Asked by mike phelps - Mon Jul 19 14:50:25 2010 - - 1 Answers - 0 Comments
A. We want qvB = kq^2/r^2 or B = kq/(vr^2) = 8.98755E9*1.6021774E-19/( 10*0.01^2) = 1.439965E-6 T. The direction of B must be perpendicular to the plane containing the two particle paths. The direction relative to the plane is best described by assuming an observer traveling in the particle velocity direction and oriented such that the electron is to the observer's left and the proton is to the right. B will then be in the observer-frame "up" direction. This will result in F(p) being directed "right" and F(e) "left"; i.e., opposing the attractive electric forces.
Answered by kirchwey - Wed Jul 21 11:01:19 2010
What are the magnitude and direction of the friction force?
Q. The force applied to the card by srping scale FA is 10.5 N. The cart no moves toward the right with a constant velocity. What are the direction and magnitude of the frictional force? I understand the direction will be to the left. But I am not sure how to find the magnitude with calculations.
Asked by boytoy123 - Sun Jun 21 05:29:49 2009 - - 1 Answers - 0 Comments
A. Because the cart is moving with constant velocity in straight line, its acceleration has to be zero and so the net force acting must be zero. So frictional force must be equal to 10.5 N in opposite direction. THe net force, F = Fa + f, where 'Fa' is applied force and f is frictional force . Because the acceleration, a of car = 0, F = ma = 0 or F = Fa + f= 0 or f = - F.
Answered by Let'slearntothink - Sun Jun 21 05:38:38 2009
Q. The force applied to the card by srping scale FA is 10.5 N. The cart no moves toward the right with a constant velocity. What are the direction and magnitude of the frictional force? I understand the direction will be to the left. But I am not sure how to find the magnitude with calculations.
Asked by boytoy123 - Sun Jun 21 05:29:49 2009 - - 1 Answers - 0 Comments
A. Because the cart is moving with constant velocity in straight line, its acceleration has to be zero and so the net force acting must be zero. So frictional force must be equal to 10.5 N in opposite direction. THe net force, F = Fa + f, where 'Fa' is applied force and f is frictional force . Because the acceleration, a of car = 0, F = ma = 0 or F = Fa + f= 0 or f = - F.
Answered by Let'slearntothink - Sun Jun 21 05:38:38 2009
What is the direction of the reflected ray which leaves the double mirror?
Q. Two plane mirrors are joined along side at a right angle. Both are perpendicular to the table top, like walls meeting at a corner. For a general angle of theta, determine the direction of the reflected ray which leaves the double mirror?
Asked by joe brown - Wed Jun 9 21:22:58 2010 - - 1 Answers - 0 Comments
A. 270-theta
Answered by douglw.geo - Wed Jun 9 21:26:25 2010
Q. Two plane mirrors are joined along side at a right angle. Both are perpendicular to the table top, like walls meeting at a corner. For a general angle of theta, determine the direction of the reflected ray which leaves the double mirror?
Asked by joe brown - Wed Jun 9 21:22:58 2010 - - 1 Answers - 0 Comments
A. 270-theta
Answered by douglw.geo - Wed Jun 9 21:26:25 2010
How do you determine magnitude and direction of a force that completely cancels a resultant force vector?
Q. In the previous question, I determined the resultant force vector has a magnitude of 55.9 N and the direction is 75.4 degrees. Now, I need to find the force of the vector that would completely cancel out that vector. Would it have the same magnitude but just a different direction?
Asked by girlmeetsworld0407 - Sun Sep 14 18:22:17 2008 - - 1 Answers - 0 Comments
A. same magnitude; opposite direction
Answered by steven_truemper - Sun Sep 14 18:25:41 2008
Q. In the previous question, I determined the resultant force vector has a magnitude of 55.9 N and the direction is 75.4 degrees. Now, I need to find the force of the vector that would completely cancel out that vector. Would it have the same magnitude but just a different direction?
Asked by girlmeetsworld0407 - Sun Sep 14 18:22:17 2008 - - 1 Answers - 0 Comments
A. same magnitude; opposite direction
Answered by steven_truemper - Sun Sep 14 18:25:41 2008
What is the direction and magnitude of the plane's velocity relative to ground?
Q. A small plane flies with a heading of 330 at an airspeed its speed relative to air of 300 km/hr. (That means that if there were no wind, the airplane would move in a direction of 30 to the west of north.) But there is a wind from the west (from 270) at 80 km/hr.
Asked by adameve - Fri Feb 20 00:15:13 2009 - - 1 Answers - 0 Comments
A. triangle, start with the winds velocity, make a horizontal line and label it 80km/hr. from the tip of this line draw another straight line that points northwest and makes a 60 degree angle with the first line. Connect the starting point of the first line to the second line and you have a triangle. label the last line 300km/hr. solve the triangle 300km/hr 16.64 west of north
Answered by Everlasting - Fri Feb 20 13:46:51 2009
Q. A small plane flies with a heading of 330 at an airspeed its speed relative to air of 300 km/hr. (That means that if there were no wind, the airplane would move in a direction of 30 to the west of north.) But there is a wind from the west (from 270) at 80 km/hr.
Asked by adameve - Fri Feb 20 00:15:13 2009 - - 1 Answers - 0 Comments
A. triangle, start with the winds velocity, make a horizontal line and label it 80km/hr. from the tip of this line draw another straight line that points northwest and makes a 60 degree angle with the first line. Connect the starting point of the first line to the second line and you have a triangle. label the last line 300km/hr. solve the triangle 300km/hr 16.64 west of north
Answered by Everlasting - Fri Feb 20 13:46:51 2009
What is the direction weather usually travels in the United States?
Q. Hi what is direction weather usually travels in the United States? AND why does it travel that way. thanks!
Asked by 1stepatatime - Wed Nov 5 01:27:39 2008 - - 2 Answers - 0 Comments
A. west to east because we are above the equator.
Answered by freewebsjunk - Thu Nov 6 12:05:28 2008
Q. Hi what is direction weather usually travels in the United States? AND why does it travel that way. thanks!
Asked by 1stepatatime - Wed Nov 5 01:27:39 2008 - - 2 Answers - 0 Comments
A. west to east because we are above the equator.
Answered by freewebsjunk - Thu Nov 6 12:05:28 2008
what is the best direction for the front of a house to face.?
Q. my desire is to build a house with the door facing the best direction to have finanical wealth and peace.
Asked by rongar - Sat Oct 20 11:11:06 2007 - - 1 Answers - 0 Comments
A. south. it is the greatest exposure to the sun. That is, of coarse you live in the norther hemisphere.
Answered by skiingted - Sat Oct 20 11:15:27 2007
Q. my desire is to build a house with the door facing the best direction to have finanical wealth and peace.
Asked by rongar - Sat Oct 20 11:11:06 2007 - - 1 Answers - 0 Comments
A. south. it is the greatest exposure to the sun. That is, of coarse you live in the norther hemisphere.
Answered by skiingted - Sat Oct 20 11:15:27 2007
What direction do you close horizontal mini blinds to prevent others from looking inside?
Q. I know depending on the direction, I can see out of the blinds when they're closed, and the other direction I can't. Is it the same from outside? So if you're not on the ground floor the blinds go down on the inside? That means if I'm able to see out of the windows, people outside can see in? I meant to say, if I can see outside between the blinds while they're closed, people outside and downstairs can see into my place?
Asked by Rebbie - Thu Mar 29 02:18:59 2007 - - 5 Answers - 0 Comments
A. first floor - they go up - on the inside second floor and above - they go down inside final answer
Answered by tomkat1528 - Thu Mar 29 02:22:56 2007
Q. I know depending on the direction, I can see out of the blinds when they're closed, and the other direction I can't. Is it the same from outside? So if you're not on the ground floor the blinds go down on the inside? That means if I'm able to see out of the windows, people outside can see in? I meant to say, if I can see outside between the blinds while they're closed, people outside and downstairs can see into my place?
Asked by Rebbie - Thu Mar 29 02:18:59 2007 - - 5 Answers - 0 Comments
A. first floor - they go up - on the inside second floor and above - they go down inside final answer
Answered by tomkat1528 - Thu Mar 29 02:22:56 2007
What is the direction of the current in wire 3? What is the direction of the magnetic field at Y?
Q. 3 wires carry a current. The direction of the currents for wires 1 & 2 point up. Wire 3 points horizontally.The current in wire 1 is smaller than current in wire 2 (I1 < I2). At point X, the magnetic field is zero (B=0). X is equidistant to all 3 wires. Y is located in same direction as wire 2.
Asked by bklonging - Sun Feb 24 23:40:35 2008 - - 1 Answers - 0 Comments
A. Using the right hand rule, the magnetic field between wires 1 and 2 is out of the page since I2>I1. Since B=0 at x equidistant from all three wires, the B field from wire 3 must be into the page at x. Using right hand rule current in wire 3 must be to the left. Assume Y is closer to wire 2 than point x is. B field to left of wire 2 is out of page, to right of wire 2 is into page
Answered by oldschool - Mon Feb 25 00:08:36 2008
Q. 3 wires carry a current. The direction of the currents for wires 1 & 2 point up. Wire 3 points horizontally.The current in wire 1 is smaller than current in wire 2 (I1 < I2). At point X, the magnetic field is zero (B=0). X is equidistant to all 3 wires. Y is located in same direction as wire 2.
Asked by bklonging - Sun Feb 24 23:40:35 2008 - - 1 Answers - 0 Comments
A. Using the right hand rule, the magnetic field between wires 1 and 2 is out of the page since I2>I1. Since B=0 at x equidistant from all three wires, the B field from wire 3 must be into the page at x. Using right hand rule current in wire 3 must be to the left. Assume Y is closer to wire 2 than point x is. B field to left of wire 2 is out of page, to right of wire 2 is into page
Answered by oldschool - Mon Feb 25 00:08:36 2008
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