How can single displacement reactions occur between only two elements, assuming one is an isotope?
Q. Text question: For any reactions that occurred, write the corresponding single displacement reaction. Easy enough for a reaction like: Mg + HCl H(subscript 2) + MgCl But then I come to a reaction between Magnesium, and Copper +2. Magnesium is above copper in the metal activity series, so it would bump it out of a polyatomic ion, however in this case there are only two elements in the equation. Any advice on solving this?
Asked by Melissa B - Tue Oct 23 15:38:14 2007 - - 1 Answers - 0 Comments
A. Cu2+ is actually associated w/ an anion in the aqueous solution which is not mentioned explicitly in the question (and there is no need to mention it!). If you keep in mind that single displacement is just another term for redox reaction you can do this easily: Cu^(2+) (aq) + Mg(s) ---> Cu(s) + Mg(2+) (aq) Since Mg is higher in the activity series, it should "reduce" Cu^(2+) (oxidation state =+2) to Cu (oxidation state = 0). For example, if you dissolve CuSO4 in water it'll become Cu^(2+) and SO4^(2-), and if it reacts with Mg, the formula equation will be: CuSO4(aq) + Mg(s) ---> Cu(s) + MgSO4(aq) [MgSO4 stays in solution as dissociated ions: Mg^(2+) and SO4^(2-)] This looks like a single displacement, doesn't it? [I used "^" to… [cont.]
Answered by Dr. K - Tue Oct 23 15:52:33 2007
Q. Text question: For any reactions that occurred, write the corresponding single displacement reaction. Easy enough for a reaction like: Mg + HCl H(subscript 2) + MgCl But then I come to a reaction between Magnesium, and Copper +2. Magnesium is above copper in the metal activity series, so it would bump it out of a polyatomic ion, however in this case there are only two elements in the equation. Any advice on solving this?
Asked by Melissa B - Tue Oct 23 15:38:14 2007 - - 1 Answers - 0 Comments
A. Cu2+ is actually associated w/ an anion in the aqueous solution which is not mentioned explicitly in the question (and there is no need to mention it!). If you keep in mind that single displacement is just another term for redox reaction you can do this easily: Cu^(2+) (aq) + Mg(s) ---> Cu(s) + Mg(2+) (aq) Since Mg is higher in the activity series, it should "reduce" Cu^(2+) (oxidation state =+2) to Cu (oxidation state = 0). For example, if you dissolve CuSO4 in water it'll become Cu^(2+) and SO4^(2-), and if it reacts with Mg, the formula equation will be: CuSO4(aq) + Mg(s) ---> Cu(s) + MgSO4(aq) [MgSO4 stays in solution as dissociated ions: Mg^(2+) and SO4^(2-)] This looks like a single displacement, doesn't it? [I used "^" to… [cont.]
Answered by Dr. K - Tue Oct 23 15:52:33 2007
What is the direction of the displacement vector?
Q. You are walking 44 m North. You then turn 60 degrees to the right and continue to walk for another 45 m. What direction is the displacement vector?
Asked by My Tien - Fri Oct 2 17:49:30 2009 - - 2 Answers - 0 Comments
A. Let X axis due East and Y axis due North. Then the components of the displacement vector V are: Vx = 45*sin60 = 38.97 m Vy = 44 + 45*cos60 = 66.5 m and tan = Vx/Vy = 0.586 = 30 North to East.
Answered by Luigi 74 - Fri Oct 2 18:04:10 2009
Q. You are walking 44 m North. You then turn 60 degrees to the right and continue to walk for another 45 m. What direction is the displacement vector?
Asked by My Tien - Fri Oct 2 17:49:30 2009 - - 2 Answers - 0 Comments
A. Let X axis due East and Y axis due North. Then the components of the displacement vector V are: Vx = 45*sin60 = 38.97 m Vy = 44 + 45*cos60 = 66.5 m and tan = Vx/Vy = 0.586 = 30 North to East.
Answered by Luigi 74 - Fri Oct 2 18:04:10 2009
How to find the magnitudes of the displacement and average velocity?
Q. A bird watcher meanders through the woods, walking 1.90 km due east, 1.71 km due south, and 2.62 km in a direction 42.5 north of west. The time required for this trip is 1.935 h. Determine the magnitudes of the bird watcher's (a) displacement and (b) average velocity.
Asked by ~Miizz RiVeRa!~ - Sat Jan 23 11:30:36 2010 - - 1 Answers - 0 Comments
A. displacement is striaght line joining start and end points velocity is displacement / time distance travelled east (or it may turn ut to be west so the sign will be negative doesnt matter) will be x = 1.9 - 2.62 cos (42.5) distance travelled south(or north) will be y = 1.71 - 2.62 sin(452.5) displacement is root (x^2 + y^2) all the best
Answered by jake z - Sat Jan 23 11:38:55 2010
Q. A bird watcher meanders through the woods, walking 1.90 km due east, 1.71 km due south, and 2.62 km in a direction 42.5 north of west. The time required for this trip is 1.935 h. Determine the magnitudes of the bird watcher's (a) displacement and (b) average velocity.
Asked by ~Miizz RiVeRa!~ - Sat Jan 23 11:30:36 2010 - - 1 Answers - 0 Comments
A. displacement is striaght line joining start and end points velocity is displacement / time distance travelled east (or it may turn ut to be west so the sign will be negative doesnt matter) will be x = 1.9 - 2.62 cos (42.5) distance travelled south(or north) will be y = 1.71 - 2.62 sin(452.5) displacement is root (x^2 + y^2) all the best
Answered by jake z - Sat Jan 23 11:38:55 2010
Displacement with two vectors that do not form a right triangle?
Q. Hello, I have an issue with a physics question that involves displacement, but the vectors do not form a right triangle. A car is driven 215km west and then 85 km southwest. What is the displacement of the car from the point of origin (magnitude and direction)? Any assistance would be appreciated. Thanks.
Asked by CuriousK? - Fri Sep 26 01:03:00 2008 - - 3 Answers - 0 Comments
A. 215km west means 215@180 degrees 85 km south of west means 85@225 degrees Vx = 215* Cos(180)+ 85* Cos(225)=-275.104 km Vy= 215* Sin(180)+ 85* Sin(225) =-60.104 km magnitude = sqr(Vx^2+Vy^2) = 281.59 km Direction: angle = atan(Vy/Vx) = 192.32 degrees CCW
Answered by Al P - Fri Sep 26 01:35:22 2008
Q. Hello, I have an issue with a physics question that involves displacement, but the vectors do not form a right triangle. A car is driven 215km west and then 85 km southwest. What is the displacement of the car from the point of origin (magnitude and direction)? Any assistance would be appreciated. Thanks.
Asked by CuriousK? - Fri Sep 26 01:03:00 2008 - - 3 Answers - 0 Comments
A. 215km west means 215@180 degrees 85 km south of west means 85@225 degrees Vx = 215* Cos(180)+ 85* Cos(225)=-275.104 km Vy= 215* Sin(180)+ 85* Sin(225) =-60.104 km magnitude = sqr(Vx^2+Vy^2) = 281.59 km Direction: angle = atan(Vy/Vx) = 192.32 degrees CCW
Answered by Al P - Fri Sep 26 01:35:22 2008
What is the largest possible displacement resulting from two displacements with magnitudes 1 m and 6 m?
Q. What is the largest possible displacement resulting from two displacements with magnitudes 1 m and 6 m? What is the smallest possible resultant?
Asked by Christoph - Wed Oct 22 22:35:50 2008 - - 2 Answers - 0 Comments
A. The largest possible displacement is 7m while the smallest possible resultant is 5m.
Answered by thunderpantz - Wed Oct 22 22:40:16 2008
Q. What is the largest possible displacement resulting from two displacements with magnitudes 1 m and 6 m? What is the smallest possible resultant?
Asked by Christoph - Wed Oct 22 22:35:50 2008 - - 2 Answers - 0 Comments
A. The largest possible displacement is 7m while the smallest possible resultant is 5m.
Answered by thunderpantz - Wed Oct 22 22:40:16 2008
What is the magnitude of the displacement of the colored checker during the triple jump?
Q. A checkerboard shows a triple jump, starting at the center of square A and ending on the center of square B. Each side of a square measures 3.6 cm. What is the magnitude of the displacement of the colored checker during the triple jump?
Asked by DP2.com - Fri Sep 5 21:05:22 2008 - - 1 Answers - 0 Comments
A. The jump is diagonal. From center of 1st square to center of 7th square is really a total of 6 diagonal lengths. A diagonal length is the hypotenuse of a triangle, 3.6 cm per side. The length of the hypotenuse is 3.6 + 3.6 = 5.09 cm 6 * 30.547 cm = 30.5 cm
Answered by MR.B - Fri Sep 5 21:30:40 2008
Q. A checkerboard shows a triple jump, starting at the center of square A and ending on the center of square B. Each side of a square measures 3.6 cm. What is the magnitude of the displacement of the colored checker during the triple jump?
Asked by DP2.com - Fri Sep 5 21:05:22 2008 - - 1 Answers - 0 Comments
A. The jump is diagonal. From center of 1st square to center of 7th square is really a total of 6 diagonal lengths. A diagonal length is the hypotenuse of a triangle, 3.6 cm per side. The length of the hypotenuse is 3.6 + 3.6 = 5.09 cm 6 * 30.547 cm = 30.5 cm
Answered by MR.B - Fri Sep 5 21:30:40 2008
What is the degree of the total displacement?
Q. During a rodeo, a clown runs 6m north, turns 55 north of east, and runs 3.5m. Then, after waiting for the bull to come near, the clown turns due east and runs 5m to exit the arena. The total displacement is 11. What is the North of East?
Asked by Jon - Sat Sep 19 17:21:15 2009 - - 1 Answers - 0 Comments
A. 1. You should draw an X Y diagram to help, so you can tell which quadrant each vector is in and assign correct sin and cos (+ and -). 2. Next convert the polar coordinates to i and j form. 6m North (90 degrees is: (6)(cos 90)i + (6)(sin 90)j both cos and sin are + 3.5m at 55 degrees is: (3.5)(cos 55)i + (3.5)(sin 55)j both cos and sine are + Add the two vectors, The result will give you the cos and sin of the angle you are looking for. Use tan= sin/cos or tan= j/i to find the angle. A check is: The squareroot of i^2 + j^2 = 11 (total displacement)
Answered by Hal - Sat Sep 19 17:55:33 2009
Q. During a rodeo, a clown runs 6m north, turns 55 north of east, and runs 3.5m. Then, after waiting for the bull to come near, the clown turns due east and runs 5m to exit the arena. The total displacement is 11. What is the North of East?
Asked by Jon - Sat Sep 19 17:21:15 2009 - - 1 Answers - 0 Comments
A. 1. You should draw an X Y diagram to help, so you can tell which quadrant each vector is in and assign correct sin and cos (+ and -). 2. Next convert the polar coordinates to i and j form. 6m North (90 degrees is: (6)(cos 90)i + (6)(sin 90)j both cos and sin are + 3.5m at 55 degrees is: (3.5)(cos 55)i + (3.5)(sin 55)j both cos and sine are + Add the two vectors, The result will give you the cos and sin of the angle you are looking for. Use tan= sin/cos or tan= j/i to find the angle. A check is: The squareroot of i^2 + j^2 = 11 (total displacement)
Answered by Hal - Sat Sep 19 17:55:33 2009
What is the resultant displacement of this physics problem?
Q. Brad walks 1.00 km [N], 0.50 km [E], 1.00 km [S], and finally 0.50 km [W] in a total time of 1.5 h. What is the resultant displacement and what is Brads average velocity? Is the resultant displacement 0 because he came back to where he started?
Asked by OMGASPITSOLJA - Sat May 2 13:09:55 2009 - - 2 Answers - 0 Comments
A. yes , the displacement = 0.
Answered by walidJ - Sat May 2 13:14:34 2009
Q. Brad walks 1.00 km [N], 0.50 km [E], 1.00 km [S], and finally 0.50 km [W] in a total time of 1.5 h. What is the resultant displacement and what is Brads average velocity? Is the resultant displacement 0 because he came back to where he started?
Asked by OMGASPITSOLJA - Sat May 2 13:09:55 2009 - - 2 Answers - 0 Comments
A. yes , the displacement = 0.
Answered by walidJ - Sat May 2 13:14:34 2009
Can the displacement of a person s trip be zero, yet the distance involved in?
Q. Can the displacement of a person s trip be zero, yet the distance involved inthe trip be nonzero? What about the reverse situation?
Asked by Annie - Thu Oct 8 23:28:24 2009 - - 3 Answers - 0 Comments
A. Yes, the displacement of a persons trip can be zero but the distance is not zero but in reverse situation it is not possible because distance can never be zero.
Answered by dude - Thu Oct 8 23:54:59 2009
Q. Can the displacement of a person s trip be zero, yet the distance involved inthe trip be nonzero? What about the reverse situation?
Asked by Annie - Thu Oct 8 23:28:24 2009 - - 3 Answers - 0 Comments
A. Yes, the displacement of a persons trip can be zero but the distance is not zero but in reverse situation it is not possible because distance can never be zero.
Answered by dude - Thu Oct 8 23:54:59 2009
What is the displacement in the position of the boy?
Q. A boy starts from point A and moves 5 units toward the east, then turns back and moves 3 units toward the west. What is the displacement in the position of the boy? Thanks in advance for your help.
Asked by Noelle - Wed Aug 13 17:11:43 2008 - - 1 Answers - 0 Comments
A. Relative to point A the displacement is 5 units east - 3 units west = 2 units east The boy is 2 units east of point A.
Answered by Al P - Wed Aug 13 17:22:58 2008
Q. A boy starts from point A and moves 5 units toward the east, then turns back and moves 3 units toward the west. What is the displacement in the position of the boy? Thanks in advance for your help.
Asked by Noelle - Wed Aug 13 17:11:43 2008 - - 1 Answers - 0 Comments
A. Relative to point A the displacement is 5 units east - 3 units west = 2 units east The boy is 2 units east of point A.
Answered by Al P - Wed Aug 13 17:22:58 2008
What is the displacement of two vectors and an angle?
Q. A roller coaster moves 85m horizontally, then travels 45m at an angle of 30.0 degrees above the horizontal. What is its displacement from its starting point?
Asked by laurenmunro9 - Thu Oct 1 20:19:47 2009 - - 1 Answers - 0 Comments
A. Okay, in order to add these vectors and find the resultant displacement you must use the method of components. Remember, always draw a picture, always. In this one, remember the tip-to-tail method. Place all the vectors head to end, the tip of one vector touching the tail of another. First, make a small chart ==x|y -A_|_ -B_|_ -R_|_ In this chart you will put the X-Y Components of your two vectors. Your first vector is a displacement along the X axis of 85m, there is no pitch from the x-axis so the vector and its x component is the same. Remember, a component is the projection of a vector perpendicular to the x and y axes. Sort of similar to its shadows if it had one. Therefore your chart for your vector A (85m horizontally) should… [cont.]
Answered by Ian Leahy - Mon Oct 5 19:58:48 2009
Q. A roller coaster moves 85m horizontally, then travels 45m at an angle of 30.0 degrees above the horizontal. What is its displacement from its starting point?
Asked by laurenmunro9 - Thu Oct 1 20:19:47 2009 - - 1 Answers - 0 Comments
A. Okay, in order to add these vectors and find the resultant displacement you must use the method of components. Remember, always draw a picture, always. In this one, remember the tip-to-tail method. Place all the vectors head to end, the tip of one vector touching the tail of another. First, make a small chart ==x|y -A_|_ -B_|_ -R_|_ In this chart you will put the X-Y Components of your two vectors. Your first vector is a displacement along the X axis of 85m, there is no pitch from the x-axis so the vector and its x component is the same. Remember, a component is the projection of a vector perpendicular to the x and y axes. Sort of similar to its shadows if it had one. Therefore your chart for your vector A (85m horizontally) should… [cont.]
Answered by Ian Leahy - Mon Oct 5 19:58:48 2009
What is the displacement of the blue piston?
Q. If the blue cylinder has 2x the diameter of the red cylinder, and the red piston is moved a displacement of 4cm. and also, If the blue cylinder has 1/2x the diameter of the red cylinder, and the red piston is moved a displacement of 3cm The teacher didn't give any initial or final position. So I guess it can be anything. The purpose is to investigate the relationship between the cylinder diameter and the range of motion of a piston in a hydraulic system. The unit these questions are from is Hydraulics and Pneumatics.
Asked by kidfrom1990 - Fri Jan 8 12:13:04 2010 - - 2 Answers - 0 Comments
A. You need to give more information. What is the initial position in the cylinder? What is the boundary condition of the piston's motion? Isothermal? Isobaric? Adiabatic/isentropic? Polytropic (if so, what is n)? Spring constrained motion?
Answered by gintable - Fri Jan 8 17:49:28 2010
Q. If the blue cylinder has 2x the diameter of the red cylinder, and the red piston is moved a displacement of 4cm. and also, If the blue cylinder has 1/2x the diameter of the red cylinder, and the red piston is moved a displacement of 3cm The teacher didn't give any initial or final position. So I guess it can be anything. The purpose is to investigate the relationship between the cylinder diameter and the range of motion of a piston in a hydraulic system. The unit these questions are from is Hydraulics and Pneumatics.
Asked by kidfrom1990 - Fri Jan 8 12:13:04 2010 - - 2 Answers - 0 Comments
A. You need to give more information. What is the initial position in the cylinder? What is the boundary condition of the piston's motion? Isothermal? Isobaric? Adiabatic/isentropic? Polytropic (if so, what is n)? Spring constrained motion?
Answered by gintable - Fri Jan 8 17:49:28 2010
What is the displacement of the end of the spring due to the weight of the mass?
Q. An object of mass M=4.3 kg is suspended from a spring of spring constant k = 1.4 N/m. What is the displacement of the end of the spring due to the weight of the mass?
Asked by Ari - Fri Oct 16 13:53:04 2009 - - 1 Answers - 0 Comments
A. You gotta calculate it with this formula mg = kx We're looking for the displacement So x = mg/k X= 4.3*9.8/1.4= 30.1 N That is =)
Answered by Katy - Fri Oct 16 14:25:46 2009
Q. An object of mass M=4.3 kg is suspended from a spring of spring constant k = 1.4 N/m. What is the displacement of the end of the spring due to the weight of the mass?
Asked by Ari - Fri Oct 16 13:53:04 2009 - - 1 Answers - 0 Comments
A. You gotta calculate it with this formula mg = kx We're looking for the displacement So x = mg/k X= 4.3*9.8/1.4= 30.1 N That is =)
Answered by Katy - Fri Oct 16 14:25:46 2009
What is its final displacement from the origin?
Q. A delivery truck travels 19 blocks north, 18 blocks west and 18 blocks south. What is its final displacement from the origin? Assume the blocks are equal length. Magnitude=___blocks Direction=___ (counterclockwise from east is positive)
Asked by fatalfairie7 - Wed Feb 6 15:57:07 2008 - - 2 Answers - 0 Comments
A. Its going to be 18 blocks west and 1 block north, so the magnitude is going to be sqrt(18^2 +1^2) = 18.028 blocks tan^-1(1/18)= -3.18 degrees, +180 = 176.8 degrees
Answered by Tom S - Wed Feb 6 16:07:39 2008
Q. A delivery truck travels 19 blocks north, 18 blocks west and 18 blocks south. What is its final displacement from the origin? Assume the blocks are equal length. Magnitude=___blocks Direction=___ (counterclockwise from east is positive)
Asked by fatalfairie7 - Wed Feb 6 15:57:07 2008 - - 2 Answers - 0 Comments
A. Its going to be 18 blocks west and 1 block north, so the magnitude is going to be sqrt(18^2 +1^2) = 18.028 blocks tan^-1(1/18)= -3.18 degrees, +180 = 176.8 degrees
Answered by Tom S - Wed Feb 6 16:07:39 2008
Why the effect of turbocharger in increasing the torque is more than engine displacement?
Q. For example usually factories increase the size of engine to get more torque,but by installing turbochargers the torque increases more than that of increasing the displacement.I want to know the reason why turbos or superchargers increase the torque so much despite smaller displacements.
Asked by lambo l - Mon Nov 19 13:16:24 2007 - - 1 Answers - 0 Comments
A. Well, turob- and super-chargers pack extra fuel/air mixture into the engine, and changing the displacement will simply give more room for fuel. Both will put about the same amount of fuel into the engine, but packing it in, as these accesories do, will, also, make higher compression, and drive the piston down faster. (If you want to turbo- or super-charge your car, you should supercharge it to eliminate engine lag.)
Answered by FordGuy - Mon Nov 19 21:54:56 2007
Q. For example usually factories increase the size of engine to get more torque,but by installing turbochargers the torque increases more than that of increasing the displacement.I want to know the reason why turbos or superchargers increase the torque so much despite smaller displacements.
Asked by lambo l - Mon Nov 19 13:16:24 2007 - - 1 Answers - 0 Comments
A. Well, turob- and super-chargers pack extra fuel/air mixture into the engine, and changing the displacement will simply give more room for fuel. Both will put about the same amount of fuel into the engine, but packing it in, as these accesories do, will, also, make higher compression, and drive the piston down faster. (If you want to turbo- or super-charge your car, you should supercharge it to eliminate engine lag.)
Answered by FordGuy - Mon Nov 19 21:54:56 2007
How do you get relocation displacement assistance?
Q. I live in Anaheim and I need to get assistance for displacement of our home, lots of us will be homeless but the City isnt helping, the Atty.JW said we had to sue them to get it. Ca Code gov. 7260-7277
Asked by ChristiCarlClub - Sat Sep 30 08:19:40 2006 - - 1 Answers - 0 Comments
A. I would go to the top, ie federal govt. Uniform Relocation Assistance and Real Property Acquisition Policies Act of 1970 This website: provided by HUD has contact information that might help.
Answered by Kevin H - Sat Sep 30 08:33:49 2006
Q. I live in Anaheim and I need to get assistance for displacement of our home, lots of us will be homeless but the City isnt helping, the Atty.JW said we had to sue them to get it. Ca Code gov. 7260-7277
Asked by ChristiCarlClub - Sat Sep 30 08:19:40 2006 - - 1 Answers - 0 Comments
A. I would go to the top, ie federal govt. Uniform Relocation Assistance and Real Property Acquisition Policies Act of 1970 This website: provided by HUD has contact information that might help.
Answered by Kevin H - Sat Sep 30 08:33:49 2006
How do you find the displacement when a non-linear path is travelled?
Q. If, for example, you were to move 45 metres north, then 30 metres west, what would the algorithm be for finding the displacement?
Asked by Brynn - Mon Jan 19 20:32:21 2009 - - 1 Answers - 0 Comments
A. solve the triangle I suggest Pythagoras 45^2 + 30^2 = displacement ^2 tan^-1 theta = 30/45 = 33.7 degrees west of north
Answered by OldPilot - Mon Jan 19 20:45:01 2009
Q. If, for example, you were to move 45 metres north, then 30 metres west, what would the algorithm be for finding the displacement?
Asked by Brynn - Mon Jan 19 20:32:21 2009 - - 1 Answers - 0 Comments
A. solve the triangle I suggest Pythagoras 45^2 + 30^2 = displacement ^2 tan^-1 theta = 30/45 = 33.7 degrees west of north
Answered by OldPilot - Mon Jan 19 20:45:01 2009
How do you find spring constant and resonance frequency given mass and displacement?
Q. The mass is .1 kg, and the displacement is .3 m--what equations would I use to find the spring constant and the resonance frequency? Thanks!
Asked by Nahma - Mon Sep 28 09:32:11 2009 - - 1 Answers - 0 Comments
A. looks like you have been provided with inadequate information...try asking for amount of force applied to bring the displacement
Answered by harish - Tue Sep 29 09:29:31 2009
Q. The mass is .1 kg, and the displacement is .3 m--what equations would I use to find the spring constant and the resonance frequency? Thanks!
Asked by Nahma - Mon Sep 28 09:32:11 2009 - - 1 Answers - 0 Comments
A. looks like you have been provided with inadequate information...try asking for amount of force applied to bring the displacement
Answered by harish - Tue Sep 29 09:29:31 2009
How can I calculate force on a spring given the mass and displacement?
Q. Please help! I have a Physics I lab due tomorrow on Simple Harmonic Motion. I simply cannot understand how to find the force on a spring when having measured the mass on the spring and the displacement each mass produces on the spring.
Asked by savannah* - Tue Dec 18 17:17:25 2007 - - 5 Answers - 0 Comments
A. Hooke's law tells us that the force on a spring is directly proportion to the displacement: F=kx, where k is a constant specific to each spring. Your specific question is confusing as it makes no mention of the spring constant, and uses mass instead of force. (F=9.8*M, for Newtons and Kilograms).
Answered by Hermoderus - Tue Dec 18 17:24:24 2007
Q. Please help! I have a Physics I lab due tomorrow on Simple Harmonic Motion. I simply cannot understand how to find the force on a spring when having measured the mass on the spring and the displacement each mass produces on the spring.
Asked by savannah* - Tue Dec 18 17:17:25 2007 - - 5 Answers - 0 Comments
A. Hooke's law tells us that the force on a spring is directly proportion to the displacement: F=kx, where k is a constant specific to each spring. Your specific question is confusing as it makes no mention of the spring constant, and uses mass instead of force. (F=9.8*M, for Newtons and Kilograms).
Answered by Hermoderus - Tue Dec 18 17:24:24 2007
What type of fault has the displacement along the tilt of the fault plane?
Q. What type of fault has the displacement along the tilt of the fault plane?
Asked by ricojsuave - Wed Feb 27 01:13:53 2008 - - 2 Answers - 0 Comments
A. It really is contingent on what you are truely asking. If by tilt you mean the Dip of the fault plane and by "along" you mean a vertical plane then the answer would be a normal fault (if the hanging wall moves upward) or a reverse fault (if the hanging wall moves downward). However, if what you meant to say was that the hanging wall travels horizontally in relation to the other fault block then you are dealing with a Strike Slip Fault.
Answered by Trip1050 - Thu Feb 28 12:41:33 2008
Q. What type of fault has the displacement along the tilt of the fault plane?
Asked by ricojsuave - Wed Feb 27 01:13:53 2008 - - 2 Answers - 0 Comments
A. It really is contingent on what you are truely asking. If by tilt you mean the Dip of the fault plane and by "along" you mean a vertical plane then the answer would be a normal fault (if the hanging wall moves upward) or a reverse fault (if the hanging wall moves downward). However, if what you meant to say was that the hanging wall travels horizontally in relation to the other fault block then you are dealing with a Strike Slip Fault.
Answered by Trip1050 - Thu Feb 28 12:41:33 2008
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Routine radiographs of the pelvis or hip can demonstrate acute separation of the ischial apophysis and quantify the degree of displacement . The fracture fragment is identified as a curved sharply marginated piece of bone adjacent to or displaced from ...
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