When would 2 concurrent forces and the equilibrant vector be equal in magnitude?
Q. When would 2 concurrent forces and the equilibrant vector be equal in magnitude?
Asked by kimkonnoth - Thu Oct 16 21:03:06 2008 - - 2 Answers - 0 Comments

A. There are a number of possibilities. One that comes to mind is if the 2 initial vectors are at an angle of 120 degrees with each other, then a third vector at 120 degrees to each of the 2 initial vectors will cancel them if the magnitudes are equal. .
Answered by billrussell42 - Thu Oct 16 21:16:53 2008

Can you give us why questions about adding force and equilibrant?
Q. Can you give us why questions about adding force and equilibrant?
Asked by ucanwrite2us - Tue Sep 4 11:05:35 2007 - - 1 Answers - 0 Comments

A. why would 3 newtons to the north be matched by 3 newtons of force to the south??? ??? ??? surely more info needed
Answered by pat_arab - Fri Sep 7 11:20:07 2007

Equilibrium and equilibrant -- what are they and what are their differences?
Q. Equilibrium and equilibrant -- what are they and what are their differences?
Asked by Liz - Thu Jan 25 18:47:15 2007 - - 1 Answers - 0 Comments

A. I think one is a noun and one is an adjective (which doesn't get much play in common speech).
Answered by ( )Mistress Bekki - Thu Jan 25 19:00:51 2007

A force of 92 makes an angle of 8* w/ a force of 12. What is the angle of the equilibrant w/ the first force?
Q. A force of 92 makes an angle of 8* w/ a force of 12. What is the angle of the equilibrant w/ the first force?
Asked by lauralunatic1992 - Mon Dec 8 21:53:13 2008 - - 1 Answers - 0 Comments

A. It tries to use this tool online: Give yourself the procedure, you resolve the problem and surely I believe that you will stay happy, hope that it serves you, bye-bye! =).
Answered by unknown - Fri Dec 12 21:50:37 2008

How do you find the equilibrant of the following forces?
Q. F1 61.0 N at 17.0 north of east F2 38.0 N at 64.0 north of east F3 54.0 N at 8.0 west of north
Asked by Natalie - Sun Feb 8 12:35:03 2009 - - 2 Answers - 0 Comments

A. use complex numbers and resolve them.
Answered by ashfaq f - Sun Feb 8 12:42:21 2009

what is the equilibrant or the upward reaction force of the nail?
Q. what is the equilibrant or the upward reaction force of the nail?
Asked by capri_korn88 - Sun Feb 12 01:12:15 2006 - - 1 Answers - 0 Comments

A. you will have to expand on your question (e.i. what is the downward action force on the nail?)
Answered by cmercer8 - Sun Feb 12 01:19:00 2006

Two vectors (equilibrant) ? Urgent!?
Q. How can I find two vectors which give an equilibrant in the first quadrant? Thanks.
Asked by drift - Fri Feb 6 14:06:33 2009 - - 1 Answers - 0 Comments

A. The easiest way would be to have two vectors in the third quadrant. The resultant would be in the third quadrant, so the equilibrant would be in the first quadrant. Therer are many other options, such as one vector in the second quadrant and a second vector in the fourth quadrant, of such magnitude and direction that the resultant is in the third quadrant, giving an equilibrant in the first quadrant. Any two vectors, which have their resultant in the third quadrant, will have an equilibrant in the first quadrant
Answered by Trevor H - Fri Feb 6 15:02:51 2009

Two horizontal guy wires are attached to a pole.What is the direction of the forces?
Q. Two horizontal guy wires are attached to a pole. The first exerts a force of 36 N and the second a force of 24 N. a)What is the direction of these forces when they produce the smallest resultant? b)At this point, what is the equilibrant of these forces?
Asked by crempel2007 - Thu May 15 00:15:56 2008 - - 2 Answers - 0 Comments

A. given a pole no matter what length... the least resultant is when the guy wires are in opposing directions... horizontal is the clue here...therefor... ---[]--- like such... the pole has guy wires on opposite sides of the pole in one spot... center for convenence of aurgument... 24 newtons to right and 36 n to left... the resultant is 12n to the left... center of the resultant is 24 n + 36 n devided by 2 giving 30 n on the resultant system... if opposite sides are in different locations... wud cause rotation of the pole...
Answered by Dennis C - Thu May 15 02:14:14 2008

Equilibrant and vectors?
Q. Knowing vector A = 98 grams @ 141 degrees, vector B = (76.2) x unit vectors + (-61.7) y unit vectors, and vector c = (-150) x unit vector + (-110) y unit vector... C is also measured in grams for its magnitude. What is the x-component of the Equilibrant of A+B+C?? in grams
Asked by shebareba2144 - Mon Jan 29 15:46:32 2007 - - 1 Answers - 0 Comments

A. 12
Answered by da_hammerhead - Mon Jan 29 16:04:56 2007

equilibrant direction (angle)? (urgent)?
Q. If I have a force A which is 30 kg and makes 0 angle with respect to x-axis, and a Force B which makes 40 kg and has an angle of 90 with respect to x-axis and the resultant I found was 50. Then what would be the equilibrant direction (angle)? i know it's supposed to be opposite of the resultant, but how do I finid the angle? Thanks. how did you get 53.3 degrees?
Asked by drift - Fri Feb 6 00:28:28 2009 - - 2 Answers - 1 Comments

A. "I have a force A which is 30 kg" Assuming forces: 30 N @ 0 40 N@ 90 Resultant = 50 N @ 53.3 degrees equilibrant: 50 N @ 233.3 degrees Fy = 40 N Fx = 30 N angle = Arctan(Fy/Fx) = 53.3 degrees equilibrant angle = 180 + 53.3 degrees Need more help, let me know.
Answered by Al P - Fri Feb 6 00:44:23 2009

find the equilibrant of: -4 vector of 130 -6 to the vector of -220?
Q. find the equilibrant of: -4 vector of 130 -6 to the vector of -220?
Asked by mandy - Tue Sep 18 20:45:29 2007 - - 2 Answers - 1 Comments

A. Vectors are:- a = - 4 (cos 130 + i sin 130 ) b = - 6 (cos 140 + i sin 140 ) a = 2.57 - 3.064 i b = 4.596 - 3.86 i a + b = 7.166 - 6.924 i
Answered by como - Sat Sep 22 15:55:27 2007

Suppose you pull a wagon along a horizontal sidewalk. What is the force that pulls the wagon forward?
Q. Is it the resultant, vertical component, equilibrant, or horizontal component?
Asked by * B the Change * - Fri Nov 20 17:07:27 2009 - - 1 Answers - 0 Comments

A. The horizontal component. This is the component that tends to pull the wagon horizontally. The vertical component tends to lift up on the wagon.
Answered by Harold - Fri Nov 20 17:13:31 2009

Vectors and Equilibrant?
Q. For a Physics lab, we were given these 3 vectors which we had to solve graphically to find the resultant. Then we have to fill up cups with the correct masses of dirt and use a force table to determine if we calculated the equilibrant correctly. My vectors were: 380g at 100 , 450g at 240 , and 525 at 352 . My first trial was wrong. I've gone through and drawn the graph again. This time, I got the resultant to be 265g at 342 , and the equilibrant to be 265g and 162 . But, I checked using compontents and got a different answer. And when I used online vector calculators, I got 3 more different answers. Can someone tell me what I'm doing wrong? Here's a scan of the diagram that I drew...
Asked by orlandoluvr_1990 - Wed Dec 12 16:03:20 2007 - - 1 Answers - 0 Comments

A. Solving this with trig to three decimal places, I get the point (-88.550, 228.905), which is rather close to your first graphic solution. This translates to roughly 245g at 339 degrees. Components: (374.227, -65.986) (-389.711, -225.000) (-73.066, 519.891) I hope this helps as a check on your computations.
Answered by norcekri - Wed Dec 12 17:22:57 2007

what does equilibrant do?
Q. what does equilibrant do?
Asked by ni - Wed Nov 15 21:00:03 2006 - - 3 Answers - 0 Comments

A. a counterbalancing force or system of forces.
Answered by jenn - Wed Nov 15 21:05:54 2006

what is meant by an equilibrant?
Q. what is meant by an equilibrant?
Asked by dodynaemahmed - Sat Jan 26 04:17:45 2008 - - 1 Answers - 0 Comments

A. If a system of forces is not in equilibrium, then it may be brought into equilibrium by the application of an 'equilibrant'. In other words the equilibrant is a force which is equal but opposite to the resultant force of a system.
Answered by clausiusminkowski - Sat Jan 26 04:45:40 2008

Can anyone help my questions with vectors?
Q. A 46N force acts S32oW while a 56N force acts S40oE. Calculate the magnitude and direction of the equilibrant.
Asked by mimi_87_99 - Sat Oct 13 23:06:14 2007 - - 1 Answers - 0 Comments

A. The step by step explanantion and solution to your problem can be reviewed at the resource provided for you below. Good luck!
Answered by unknown - Tue Oct 16 17:00:21 2007

what is meant by a equilibrant?
Q. what is meant by a equilibrant?
Asked by ahmed dr - Sat Jan 26 07:25:51 2008 - - 1 Answers - 0 Comments

A. A force that is capable of balancing a system of forces to produce equilibrium or stability. The adjustment is an equilibrant when it balances the forces in the subluxation.
Answered by fairy_dust - Sat Jan 26 07:34:56 2008

If F1= 40 N to the right, F2= 60 N to the right, and F3 = 160 N to the left, what is the resultant force?
Q. find the equilibrant of the three forces
Asked by tobi - Sun Dec 2 07:44:42 2007 - - 7 Answers - 0 Comments

A. Forces to the right =F1+F2=60+40=100N Forces to the left=F3=160N sum of forces on point A=160-100 =60N to the left.
Answered by E.M.M. - Sun Dec 2 08:21:39 2007

two forces act on an object, An 85N force acts at 100degrees. A 65N force acts at 25degrees.?
Q. what is the magnitude and direction of the resultant force? what is the magnitude and direction of the equilibrant force?
Asked by lululover9365 - Mon Jan 25 18:26:26 2010 - - 1 Answers - 0 Comments

A. sum Fx: 85* Cos(100)+ 65* Cos( 25) =44.1499110556928 N sum Fy: 85* Sin(100)+ 65* Sin( 25) =111.178846019183 N F_r = Sqrt(Fx^2+Fy^2) = 119.624N @Atan(Fy/Fx) = 68.34 degrees CCW F_e= Sqrt(Fx^2+Fy^2) = 119.624N @180+68.34 = 248.34 degrees CCW
Answered by Al P - Mon Jan 25 18:38:43 2010

Find the resultant using the rectangular component method...?
Q. degrees = 30 f1 = f2 = 10N F3 = 20N Find also the equilibrant of F1,F2, and F3...
Asked by galadriel - Wed Jul 2 20:15:10 2008 - - 1 Answers - 0 Comments

A. Galadriel-- Do you mean for all three vector forces to have an angular measure of 30 degrees? Please list the forces and their angle...(F,theta) The answer will be... Fx (total) = Sum(F1 cos(theta1) + F2 cos(theta2) +...+Fn cos(thetan)) Fy (total) = Sum(F1 sin(theta1) + F2 sin(theta2) +...+Fn sin(thetan)) Then resolve these into one vector as... F(magnitude) = SQRT(Fx total ^2 + Fy total ^2) angle = arc tan(Fy/Fx) making sure to be in the correct quadrant with correct sign... a diagram is MOST useful. gl. -Fred
Answered by getfreducated - Wed Jul 2 20:28:14 2008