What is the resultant speed of the ferry?
Q. A ferry with a velocity of 10.0 m/s travels from one side of the river to the other side at a point directly across. When a current is flowing down the river, the ferry's captain directs the boat at an angle up river so that the ferry arrives at the correct landing point. If the speed of the river water is 2.00 m/s, what is the resultant speed of the ferry?
Asked by Mara M - Thu Mar 26 23:08:57 2009 - - 1 Answers - 0 Comments
A. v = sqrt(10.0^2 - 2.0^2) v = 9.80 m/s
Answered by sweetwater - Sat Mar 28 02:29:13 2009
Q. A ferry with a velocity of 10.0 m/s travels from one side of the river to the other side at a point directly across. When a current is flowing down the river, the ferry's captain directs the boat at an angle up river so that the ferry arrives at the correct landing point. If the speed of the river water is 2.00 m/s, what is the resultant speed of the ferry?
Asked by Mara M - Thu Mar 26 23:08:57 2009 - - 1 Answers - 0 Comments
A. v = sqrt(10.0^2 - 2.0^2) v = 9.80 m/s
Answered by sweetwater - Sat Mar 28 02:29:13 2009
Find the resultant speed and direction of the airplane. (pre-cal)?
Q. An airplane has an airspeed of 700 km per hour at a bearing of 60 degress. The wind velocity is 30 km per hour from the west. Find the resultant speed and direction of the airplane.
Asked by Vicky W - Mon Jan 21 02:38:16 2008 - - 1 Answers - 0 Comments
A. ok, at 60 degrees, the sin is (sqroot3)/2 (approx 0.866), and the cosine is 1/2 (exactly 0.5). multiply those by the speed of the airplane to get the components operating in the N/S and E/W direction. We get 606.22 for the sine (north) and 350 for the cosine(east). Now, if the wind is from the west, it is going east, so that increases the eastward component to 350 + 30 = 380 Using the Pythagorean theorem and the new components, we get (380)^2 + (606.22)^2 = (newspeed)^2 or 367500 + 144400 = x^2 511900 = x^2 so x = sqroot 511900 = approx 715.47 sory it took so long to get to it, and Hope that helps ya!
Answered by p lawes - Wed Jan 23 23:10:03 2008
Q. An airplane has an airspeed of 700 km per hour at a bearing of 60 degress. The wind velocity is 30 km per hour from the west. Find the resultant speed and direction of the airplane.
Asked by Vicky W - Mon Jan 21 02:38:16 2008 - - 1 Answers - 0 Comments
A. ok, at 60 degrees, the sin is (sqroot3)/2 (approx 0.866), and the cosine is 1/2 (exactly 0.5). multiply those by the speed of the airplane to get the components operating in the N/S and E/W direction. We get 606.22 for the sine (north) and 350 for the cosine(east). Now, if the wind is from the west, it is going east, so that increases the eastward component to 350 + 30 = 380 Using the Pythagorean theorem and the new components, we get (380)^2 + (606.22)^2 = (newspeed)^2 or 367500 + 144400 = x^2 511900 = x^2 so x = sqroot 511900 = approx 715.47 sory it took so long to get to it, and Hope that helps ya!
Answered by p lawes - Wed Jan 23 23:10:03 2008
calculating resultant speed?
Q. an aeroplane heads due north at a speed of 200m/s. a wind is blowing north east and has speed 50m/s a) calculate the resultant speed of the aeroplane b) find the bearingon which the aeroplane actually moves.
Asked by Scouting-For-Boys - Sun Apr 6 10:18:04 2008 - - 1 Answers - 0 Comments
A. a^2=b^2+c^2-2abcosA =50^2+200^2-2000cos135 =42500+2000/sqrt2 bearing sin135/42500+2000/sqrt2=s inB/50 sinB=50(1/sqrt2*42500+200 0/sqrt2) solve for B
Answered by someone else - Sun Apr 6 10:28:14 2008
Q. an aeroplane heads due north at a speed of 200m/s. a wind is blowing north east and has speed 50m/s a) calculate the resultant speed of the aeroplane b) find the bearingon which the aeroplane actually moves.
Asked by Scouting-For-Boys - Sun Apr 6 10:18:04 2008 - - 1 Answers - 0 Comments
A. a^2=b^2+c^2-2abcosA =50^2+200^2-2000cos135 =42500+2000/sqrt2 bearing sin135/42500+2000/sqrt2=s inB/50 sinB=50(1/sqrt2*42500+200 0/sqrt2) solve for B
Answered by someone else - Sun Apr 6 10:28:14 2008
Boat Actual speed and Resultant speed (Please Help)?
Q. A boat whose speed in still water = 10m/s on the course N 30 deg W. If current speed = 2m/s flowing in the direction S 45 deg E. a. What is actual speed of the boat? b. If further, a wind of speed 4m/s blows toward the north, what would be the resultant speed of the boat?
Asked by Mike T - Thu Jan 1 08:01:19 2009 - - 2 Answers - 0 Comments
A. Boat in still water. North component = 10cos(30) = 5SQRT(3) West component = 10sin(30) = 5 Set up a coordinate system so that X is East and Y is North. So the above vector is: V = -5i + 5SQRT(3)j Now do the flow of the water in this same coordinate system. W = SQRT(2)i - SQRT(2)j Now just add these vectors. a. Vector Speed = V + W Vector Speed = [SQRT(2) - 5]i + [5SQRT(3) - SQRT(2)]j This is the vector speed so find the magnitude: Speed = SQRT{ [SQRT(2) - 5]^2 + [5SQRT(3) - SQRT(2)]^2} Speed = SQRT{2 + 25 - 10SQRT(2) + 75 + 2 - 10SQRT(6)} Speed = SQRT{104 - 10SQRT(2) - 10SQRT(6) } Speed = SQRT{65.363 } Speed = 8.085 b. The wind is 4j so add this to the vector in "a". Vector Speed = [SQRT(2) - 5]i + [4 + 5SQRT(3) - SQRT(2)]j And… [cont.]
Answered by Captain Mephisto - Thu Jan 1 09:17:59 2009
Q. A boat whose speed in still water = 10m/s on the course N 30 deg W. If current speed = 2m/s flowing in the direction S 45 deg E. a. What is actual speed of the boat? b. If further, a wind of speed 4m/s blows toward the north, what would be the resultant speed of the boat?
Asked by Mike T - Thu Jan 1 08:01:19 2009 - - 2 Answers - 0 Comments
A. Boat in still water. North component = 10cos(30) = 5SQRT(3) West component = 10sin(30) = 5 Set up a coordinate system so that X is East and Y is North. So the above vector is: V = -5i + 5SQRT(3)j Now do the flow of the water in this same coordinate system. W = SQRT(2)i - SQRT(2)j Now just add these vectors. a. Vector Speed = V + W Vector Speed = [SQRT(2) - 5]i + [5SQRT(3) - SQRT(2)]j This is the vector speed so find the magnitude: Speed = SQRT{ [SQRT(2) - 5]^2 + [5SQRT(3) - SQRT(2)]^2} Speed = SQRT{2 + 25 - 10SQRT(2) + 75 + 2 - 10SQRT(6)} Speed = SQRT{104 - 10SQRT(2) - 10SQRT(6) } Speed = SQRT{65.363 } Speed = 8.085 b. The wind is 4j so add this to the vector in "a". Vector Speed = [SQRT(2) - 5]i + [4 + 5SQRT(3) - SQRT(2)]j And… [cont.]
Answered by Captain Mephisto - Thu Jan 1 09:17:59 2009
If a car is traveling with a constant speed of 5.53 m/s in the Westward direction, what's the resultant force?
Q. If a car is traveling with a constant speed of 5.53 m/s in the Westward direction, what is the resultant force(N) acting on it? Ignore friction
Asked by Lynn - Sun Sep 13 13:56:59 2009 - - 1 Answers - 0 Comments
A. If the car has a constant speed ( read constant velocity) then the acceleration is 0. If the acceleration is 0, then there is no resultant force acting on the car. You can derive this from the Newton 11 equation: Force (resultant) = mass * acceleration. If acceleration is 0, mass * acceleration = 0. Therefore the resultant force = 0
Answered by Trevor H - Sun Sep 13 15:14:19 2009
Q. If a car is traveling with a constant speed of 5.53 m/s in the Westward direction, what is the resultant force(N) acting on it? Ignore friction
Asked by Lynn - Sun Sep 13 13:56:59 2009 - - 1 Answers - 0 Comments
A. If the car has a constant speed ( read constant velocity) then the acceleration is 0. If the acceleration is 0, then there is no resultant force acting on the car. You can derive this from the Newton 11 equation: Force (resultant) = mass * acceleration. If acceleration is 0, mass * acceleration = 0. Therefore the resultant force = 0
Answered by Trevor H - Sun Sep 13 15:14:19 2009
What are the resultant speed and direction of the airplane?
Q. 1.) An airplane is headed N 60 W at a speed of 40 mph. the airplane encounters wind with a velocity of 75 mph in the direction N 40 E. What are the resultant speed and direction of the airplane? 2.) Consider the airplane described above, headed N 60 W at a speed of 400 mph. What wind velocity, in the direction of N 40 E, will produce a resultant direction of N 50 W? Explain how to use a graphing program to obtain the answer experimentally. Than explain how to obtain the answer analytically.
Asked by Bobby B - Fri Apr 25 13:39:44 2008 - - 1 Answers - 0 Comments
A. 1. 75mph*cos40 - 40mph*cos30 = x component of the airplane's new speed 75mph*sin40 + 40mph*sin30 = y component of the airplane's new speed The airplane's new speed and direction: 71.8mph at N 18.5 degrees E 2. Let the wind velocity be w, -400cos30 + wcos50 = -50cos40 w = (-50cos40 + 400cos30)/cos 50 w = 479 mph
Answered by Cappucino - Fri Apr 25 13:52:59 2008
Q. 1.) An airplane is headed N 60 W at a speed of 40 mph. the airplane encounters wind with a velocity of 75 mph in the direction N 40 E. What are the resultant speed and direction of the airplane? 2.) Consider the airplane described above, headed N 60 W at a speed of 400 mph. What wind velocity, in the direction of N 40 E, will produce a resultant direction of N 50 W? Explain how to use a graphing program to obtain the answer experimentally. Than explain how to obtain the answer analytically.
Asked by Bobby B - Fri Apr 25 13:39:44 2008 - - 1 Answers - 0 Comments
A. 1. 75mph*cos40 - 40mph*cos30 = x component of the airplane's new speed 75mph*sin40 + 40mph*sin30 = y component of the airplane's new speed The airplane's new speed and direction: 71.8mph at N 18.5 degrees E 2. Let the wind velocity be w, -400cos30 + wcos50 = -50cos40 w = (-50cos40 + 400cos30)/cos 50 w = 479 mph
Answered by Cappucino - Fri Apr 25 13:52:59 2008
What are the boat's Resultant speed and Direction ? ? ? ?
Q. Joe is driving his motorboat across a river. The speed of the boat in still water is 9 mi/h. The river flows directly south at 3 mi/h. If Joe heads directly west, what are the boat's resultant spped and direction? A. 9.5 mi/h ; 18 degrees south of west B. 18 mi/h ; 9.5 degrees south of west C. 18 mi/h ; 9.5 degrees north of west D. 9.5 mi/h ; 18 degrees north of west Here is the link to view the diagram: Any help would be appreciated.
Asked by Rin Rin - Fri Mar 20 11:34:37 2009 - - 1 Answers - 0 Comments
A. // tanx=3/9 x=18.4deg mag=sqrt(9+81)=9.48 (a)
Answered by vect - Fri Mar 20 11:41:21 2009
Q. Joe is driving his motorboat across a river. The speed of the boat in still water is 9 mi/h. The river flows directly south at 3 mi/h. If Joe heads directly west, what are the boat's resultant spped and direction? A. 9.5 mi/h ; 18 degrees south of west B. 18 mi/h ; 9.5 degrees south of west C. 18 mi/h ; 9.5 degrees north of west D. 9.5 mi/h ; 18 degrees north of west Here is the link to view the diagram: Any help would be appreciated.
Asked by Rin Rin - Fri Mar 20 11:34:37 2009 - - 1 Answers - 0 Comments
A. // tanx=3/9 x=18.4deg mag=sqrt(9+81)=9.48 (a)
Answered by vect - Fri Mar 20 11:41:21 2009
what is the equation for resultant velocity, speed, time and distance?
Q. i am only in 7th grade
Asked by dosty2005 - Thu Jun 4 21:51:00 2009 - - 1 Answers - 0 Comments
A. If d is the initial distance and v the initial velocity and a is the acceleration which is constant Then the distance is d = d + v t + at The velocity is v = v + at If the velocity is constant (ie a=0) then the first equation simplifies to ... d = d + v t These are the main equations In Google you might want to search Kinematics This is the field that you are talking about You might start with Wikipedia.org, The World s Encyclopedia and their page and see how much of it you understand.
Answered by David Dodeca - Thu Jun 4 23:06:01 2009
Q. i am only in 7th grade
Asked by dosty2005 - Thu Jun 4 21:51:00 2009 - - 1 Answers - 0 Comments
A. If d is the initial distance and v the initial velocity and a is the acceleration which is constant Then the distance is d = d + v t + at The velocity is v = v + at If the velocity is constant (ie a=0) then the first equation simplifies to ... d = d + v t These are the main equations In Google you might want to search Kinematics This is the field that you are talking about You might start with Wikipedia.org, The World s Encyclopedia and their page and see how much of it you understand.
Answered by David Dodeca - Thu Jun 4 23:06:01 2009
If a car is travelling with a constant speed of 29.96 m/s in the Westward direction, what is the resultant for
Q. If a car is travelling with a constant speed of 29.96 m/s in the Westward direction, what is the resultant force?
Asked by wgriffin17 - Wed Sep 13 13:03:13 2006 - - 3 Answers - 0 Comments
A. Blunt force trauma to the head where the crack head pistol whipped you before jacking your stolen car.
Answered by Louis L - Wed Sep 13 13:11:07 2006
Q. If a car is travelling with a constant speed of 29.96 m/s in the Westward direction, what is the resultant force?
Asked by wgriffin17 - Wed Sep 13 13:03:13 2006 - - 3 Answers - 0 Comments
A. Blunt force trauma to the head where the crack head pistol whipped you before jacking your stolen car.
Answered by Louis L - Wed Sep 13 13:11:07 2006
What is the resultant force of a car with a constant speed of 29.05 m/s in W direction, ignoring friction?
Q. What is the resultant force of a car with a constant speed of 29.05 m/s in W direction, ignoring friction?
Asked by Megan - Sat Sep 12 15:19:22 2009 - - 1 Answers - 0 Comments
A. well if the velocity is constant and your ignoring friction than that means the acceleration is zero and the resulting force is zero.
Answered by Ryan - Sat Sep 12 15:26:10 2009
Q. What is the resultant force of a car with a constant speed of 29.05 m/s in W direction, ignoring friction?
Asked by Megan - Sat Sep 12 15:19:22 2009 - - 1 Answers - 0 Comments
A. well if the velocity is constant and your ignoring friction than that means the acceleration is zero and the resulting force is zero.
Answered by Ryan - Sat Sep 12 15:26:10 2009
What is the resultant force on a car due to acceleration?
Q. A car of mass m=1000 slugs accelerates in 10 seconds from rest at a constant rate of speed of v=20 ft/sec. What is the resultant force on the car due to this acceleration?
Asked by Scott D - Sun Sep 14 12:27:05 2008 - - 1 Answers - 0 Comments
A. F = m (v1 - v0)/dt; where m = 1000 slugs, v1 = 20 fps, v0 = 0, and dt = 10 sec. Thus the continuous force of acceleration over the ten second interval is F = 1000*(20 - 0)/10 = 2000 lbs.
Answered by oldprof - Sun Sep 14 12:47:21 2008
Q. A car of mass m=1000 slugs accelerates in 10 seconds from rest at a constant rate of speed of v=20 ft/sec. What is the resultant force on the car due to this acceleration?
Asked by Scott D - Sun Sep 14 12:27:05 2008 - - 1 Answers - 0 Comments
A. F = m (v1 - v0)/dt; where m = 1000 slugs, v1 = 20 fps, v0 = 0, and dt = 10 sec. Thus the continuous force of acceleration over the ten second interval is F = 1000*(20 - 0)/10 = 2000 lbs.
Answered by oldprof - Sun Sep 14 12:47:21 2008
How do you find the resultant vector?
Q. An aircraft flies with a speed of 120km/h due North. A wind is blowing toward the Southwest with a speed of 20km/h. Fine the plane's resultant velocity. Help? How do i solve it with the cosine and sine? I dont even know how to get the angles to solve it! Sorry, I meant *Find the plane's resultant velocity.
Asked by Sanny C - Fri Oct 24 03:19:17 2008 - - 3 Answers - 0 Comments
A. You must use the cosine rule. c^2=a^2+b^2-(2abcosC). Angel between North and southwest is 135. c^2 = 20^2+120^2-(2x20x120cos13 5) c^2= 18194.11255 c= 134.89 km/h That would be the air speed but i am not sure what you mean by resultant velocity. If you want ground speed then it would be 106.8 km/h. To do it you would need to find the vertical and horizontal velocity of the Southwest wind. You minus the vertical velocity (14.14) from 120 then use a^2+b^2=c^2 to solve it.
Answered by Sangdi G - Fri Oct 24 03:35:11 2008
Q. An aircraft flies with a speed of 120km/h due North. A wind is blowing toward the Southwest with a speed of 20km/h. Fine the plane's resultant velocity. Help? How do i solve it with the cosine and sine? I dont even know how to get the angles to solve it! Sorry, I meant *Find the plane's resultant velocity.
Asked by Sanny C - Fri Oct 24 03:19:17 2008 - - 3 Answers - 0 Comments
A. You must use the cosine rule. c^2=a^2+b^2-(2abcosC). Angel between North and southwest is 135. c^2 = 20^2+120^2-(2x20x120cos13 5) c^2= 18194.11255 c= 134.89 km/h That would be the air speed but i am not sure what you mean by resultant velocity. If you want ground speed then it would be 106.8 km/h. To do it you would need to find the vertical and horizontal velocity of the Southwest wind. You minus the vertical velocity (14.14) from 120 then use a^2+b^2=c^2 to solve it.
Answered by Sangdi G - Fri Oct 24 03:35:11 2008
Questiom about speed/direction for geometry?
Q. Trying to figure out how to solve a set of problems. Here's an example of one of them: An airplane is flying at 400 miles per hour due west. The wind is blowing from due north at 30 miles per hour. Find the resultant speed and direction of the plane. Is this asking for the magnitude (speed) and direction in degrees via tan(-1). Would it be speed 10(sqroot of 1609) and direction of about 4.29 degrees?
Asked by pat m - Sun Dec 21 13:54:56 2008 - - 1 Answers - 0 Comments
A. You are right on target except in the heading department. The compass uses due North as a heading of zero degrees and then the numbers increase as you turn to the right. So 90 degrees is East, 180 degrees is South and West is 270 degrees. So your resultant direction of the airplane would lie between West and South. Your 4.29 degrees needs to be subtracted from the airplanes heading of 270 degrees to give a direction of 265.71 degrees. The same would also apply in the case of a boat or any vehicle using a compass for navigation. Hope this helps. gl
Answered by GL - Sun Dec 21 14:57:49 2008
Q. Trying to figure out how to solve a set of problems. Here's an example of one of them: An airplane is flying at 400 miles per hour due west. The wind is blowing from due north at 30 miles per hour. Find the resultant speed and direction of the plane. Is this asking for the magnitude (speed) and direction in degrees via tan(-1). Would it be speed 10(sqroot of 1609) and direction of about 4.29 degrees?
Asked by pat m - Sun Dec 21 13:54:56 2008 - - 1 Answers - 0 Comments
A. You are right on target except in the heading department. The compass uses due North as a heading of zero degrees and then the numbers increase as you turn to the right. So 90 degrees is East, 180 degrees is South and West is 270 degrees. So your resultant direction of the airplane would lie between West and South. Your 4.29 degrees needs to be subtracted from the airplanes heading of 270 degrees to give a direction of 265.71 degrees. The same would also apply in the case of a boat or any vehicle using a compass for navigation. Hope this helps. gl
Answered by GL - Sun Dec 21 14:57:49 2008
An object has given speed in still water. If the object attempts to travel directly North across a river of a?
Q. An object has given speed in still water. If the object attempts to travel directly North across a river of a given width, whose current is a given speed East: Calculate (a) how long it will take to reach the other side, (b) how far downstream the swimmer will land from his intended spot, and (c) the resultant velocity (magnitude and direction) as observed by someone on the shore?
Asked by smallville427 - Tue Nov 20 20:20:06 2007 - - 1 Answers - 0 Comments
A. (a) You need to divide the River width by the speed of odject in the still water to see the time taken to cross the river. Although the current is pushing you down, the time taken to cross the river is the same (b) multiply the river speed by the time taken to go down stream (c) this will be more clear if you draw a triangle indicating the distance traveled downstream and river width then use Pythagorus to calculate the third side to get the magnitude for someone on shore observing. The direction should be North-East.
Answered by SilentWater - Tue Nov 20 20:32:44 2007
Q. An object has given speed in still water. If the object attempts to travel directly North across a river of a given width, whose current is a given speed East: Calculate (a) how long it will take to reach the other side, (b) how far downstream the swimmer will land from his intended spot, and (c) the resultant velocity (magnitude and direction) as observed by someone on the shore?
Asked by smallville427 - Tue Nov 20 20:20:06 2007 - - 1 Answers - 0 Comments
A. (a) You need to divide the River width by the speed of odject in the still water to see the time taken to cross the river. Although the current is pushing you down, the time taken to cross the river is the same (b) multiply the river speed by the time taken to go down stream (c) this will be more clear if you draw a triangle indicating the distance traveled downstream and river width then use Pythagorus to calculate the third side to get the magnitude for someone on shore observing. The direction should be North-East.
Answered by SilentWater - Tue Nov 20 20:32:44 2007
Calculating force when you have a constant speed?
Q. If a car is travelling with a constant speed of 6.44 m/s in the Westward direction, what is the resultant force acting on it? Ignore friction.
Asked by Sgr - Mon Sep 14 11:22:37 2009 - - 4 Answers - 0 Comments
A. constant speed means no force is applied 1st newton law of motion states that an object move in constant velocity when no external force is applied :-)
Answered by m_one - Mon Sep 14 11:43:51 2009
Q. If a car is travelling with a constant speed of 6.44 m/s in the Westward direction, what is the resultant force acting on it? Ignore friction.
Asked by Sgr - Mon Sep 14 11:22:37 2009 - - 4 Answers - 0 Comments
A. constant speed means no force is applied 1st newton law of motion states that an object move in constant velocity when no external force is applied :-)
Answered by m_one - Mon Sep 14 11:43:51 2009
If a car is traveling westward with a constant speed of 20 m/s, what is the resultant force acting on it?
Q. see above
Asked by got_iain - Wed Oct 1 23:54:00 2008 - - 1 Answers - 0 Comments
A. As the speed is constant, there is no force. Newton's First Law: Every body continues in its state of rest or uniform motion in a straight line unless it is acted on by a force.
Answered by Rackbrane - Sat Oct 4 17:41:09 2008
Q. see above
Asked by got_iain - Wed Oct 1 23:54:00 2008 - - 1 Answers - 0 Comments
A. As the speed is constant, there is no force. Newton's First Law: Every body continues in its state of rest or uniform motion in a straight line unless it is acted on by a force.
Answered by Rackbrane - Sat Oct 4 17:41:09 2008
Is it possible that lighter objects fall faster than heavier ones in a vacuum?
Q. On one hand, some say that the force acting on heavier objects are greater. However, their inertia is also greater. Therefore, the resultant speed is the same. On the other hand, some argue that the acceleration acting on it is the same anytime. Therefore, the resultant speed is also the same. Since it is true they have greater inertia and the acceleration on it is always the same, could it be that heavier objects fall slower than lighter objects?
Asked by Br_T - Thu Dec 24 00:19:45 2009 - - 6 Answers - 0 Comments
A. No,this was tried by astronausts on the moon. Galileo postulates this theory and it was confirmed around 400 later.
Answered by EDMOND M - Thu Dec 24 02:06:11 2009
Q. On one hand, some say that the force acting on heavier objects are greater. However, their inertia is also greater. Therefore, the resultant speed is the same. On the other hand, some argue that the acceleration acting on it is the same anytime. Therefore, the resultant speed is also the same. Since it is true they have greater inertia and the acceleration on it is always the same, could it be that heavier objects fall slower than lighter objects?
Asked by Br_T - Thu Dec 24 00:19:45 2009 - - 6 Answers - 0 Comments
A. No,this was tried by astronausts on the moon. Galileo postulates this theory and it was confirmed around 400 later.
Answered by EDMOND M - Thu Dec 24 02:06:11 2009
Physics help, speed of a canoe?
Q. A person of mass m=90kg jumps from a canoe of mass M=30 kg at an angle 60 degrees to the horizontal with velocity v=2m/s. Assuming that the canoe is initially at rest and neglecting the resistance of water, find the resultant speed of the canoe.
Asked by Chris - Wed Nov 18 05:49:09 2009 - - 1 Answers - 0 Comments
A. the speed of the conoe going downstreems is equal to speed plus speed of the conoe going upstreams is equl to the speed minus.so it depends. it depends upon conoe going upstream are down stream ,
Answered by facebook - Sat Nov 21 04:43:22 2009
Q. A person of mass m=90kg jumps from a canoe of mass M=30 kg at an angle 60 degrees to the horizontal with velocity v=2m/s. Assuming that the canoe is initially at rest and neglecting the resistance of water, find the resultant speed of the canoe.
Asked by Chris - Wed Nov 18 05:49:09 2009 - - 1 Answers - 0 Comments
A. the speed of the conoe going downstreems is equal to speed plus speed of the conoe going upstreams is equl to the speed minus.so it depends. it depends upon conoe going upstream are down stream ,
Answered by facebook - Sat Nov 21 04:43:22 2009
The forces on a parachutists as he moves vertically down through air at a uniform speed of 6.0mss?
Q. Find:- a) the 2 principal forces acting on him. b) is there a resultant force acting on her? c) suggest a way that would allow her to move forward, as well as down.
Asked by DarKLighT - Thu Mar 27 05:42:09 2008 - - 1 Answers - 0 Comments
A. (a) 1) weight m g ; 2) the drag force of the air Fr (b) The speed is constant , then a = 0 and a resultant force = 0.
Answered by Luigi 74 - Thu Mar 27 06:04:54 2008
Q. Find:- a) the 2 principal forces acting on him. b) is there a resultant force acting on her? c) suggest a way that would allow her to move forward, as well as down.
Asked by DarKLighT - Thu Mar 27 05:42:09 2008 - - 1 Answers - 0 Comments
A. (a) 1) weight m g ; 2) the drag force of the air Fr (b) The speed is constant , then a = 0 and a resultant force = 0.
Answered by Luigi 74 - Thu Mar 27 06:04:54 2008
A car of mass 800 kg accelerates uniformly along a straight line from rest to a speed of 12 ms-1 in 50s?
Q. a) Calculate the acceleration of the car b) Calculate the resultant force on the car that produced this acceleration AS physics Past paper question, I'm struggling to work this question out, thanks.
Asked by Ron - Wed Oct 10 12:13:51 2007 - - 2 Answers - 0 Comments
A. a) (12m/s - 0m/s) / 50s = 0.24m/s^2 b) F = ma = 800kg(0.24m/s^2) = 192kgm/s^2 = 192N
Answered by . - Wed Oct 10 12:19:04 2007
Q. a) Calculate the acceleration of the car b) Calculate the resultant force on the car that produced this acceleration AS physics Past paper question, I'm struggling to work this question out, thanks.
Asked by Ron - Wed Oct 10 12:13:51 2007 - - 2 Answers - 0 Comments
A. a) (12m/s - 0m/s) / 50s = 0.24m/s^2 b) F = ma = 800kg(0.24m/s^2) = 192kgm/s^2 = 192N
Answered by . - Wed Oct 10 12:19:04 2007
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3c), the resultant differential expansion leads to a bending of the organ. In hardwoods, such as poplar, additional actuating mechanisms have evolved. ...
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to 145 Moreover the interface of the program is a little bizarre When I was raising the Vcore up to 1 8V the system worked stably at 150 MHz FSB the resultant speed is 2700 MHz The FSB frequency is set very precisely during overclocking By the way we had to increase the Vagp +0 1V so that the 3Dmark could be passed successfully Conclusion the
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onlyvinod56
Wed, 15 Oct 2008 07:00:00 GM
induction motor with constant speed. The Projects Forum. ... It can be done with pulleys and belts. Select pulley diameters that give you the correct . resultant speed. . First comes the hardware, then the software. beenthere ...
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